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5.0 g of sodium hydroxide ("molar mass ...

5.0 g of sodium hydroxide `("molar mass 40 g mol"^(-1)) is dissolved in little quanitity of water and the solution is diluted upto 100 mL. What is the molarity of the resulting solution ?

A

`0.1"mol dm"^(-3)`

B

`1.0"mol dm"^(-3)`

C

`0.125"mol dm"^(-3)`

D

`1.125"mol dm"^(-3)`

Text Solution

Verified by Experts

The correct Answer is:
D
Molarity is given as,
`M=("Moles of solute")/("Volume of solution (in L)")`
`M=(Wxx1000)/("m" xx "volume of solution (in mL")`
Given, W (mass of solute) =5.0g
m (molar mass of solute) = 40 g `mol^(-1)`
Volume =100 mL
`M=(5.0gxx1000)/(40xx100)`
`1.25" mol dm"^(-3)`
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  • 5.0 g of sodium hydroxide (molar mass 40 g mol) is dissolved in little quantity of water and the solution is diluted upto 100 mL. What is the molarity of the resulting solution?

    A
    `0.1" mol dm"^-3`
    B
    `1.0" mol dm"^-3`
    C
    `0.125" mol dm"^-3`
    D
    ` 1.25" mol dm"^-3`

  • 5.0 g of sodium hydroxide ( Molar mass 40 g mol^(-1) ) is dissolved in litre quantiyu of water and the solution is diluted up to 100 mL what is the molarity of the resulting solutions ?

    A
    `0.1 mol dm^(3)`
    B
    `1.0 mol dm ^(-3)`
    C
    `0.125 mol dm ^(-3)`
    D
    ` 1.25 mol dm`

  • 5.0 g of sodium hydroxide (molar mass 40 g mol^(-1) ) is dissolved in little quantity of water and the molarity of the resulting solution?

    A
    0.1 mol `dm^(-3)`
    B
    1.0 mol `dm^(-3)`
    C
    0.125 mol `dm^(-3)`
    D
    1.25 mol `dm^(-3)`
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