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The highest Mn fluoride is MnF(4) where ...

The highest Mn fluoride is `MnF_(4)` where as the highest oxide is `Mn_(2)O_(7)` Why?

Text Solution

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The ability of oxygen to stabilize the high oxidation states exceeds that of fluoride. Thus the highest Mn fluoride is `MnF_(4)` where as highest oxide is `Mn_(2)O_(7)`.
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Knowledge Check

  • The highest oxidation state of fluorine is

    A
    `-1`
    B
    `+1`
    C
    0
    D
    `+2`

  • The pair of compounds having metals in their highest oxidation state is

    A
    `MnO_(2)` and `CrO_2 Cl_2`
    B
    `[FeCl_(4)]^(-)` and `Co_(2) O_(3)`
    C
    `[Fe(CN)_(6)]^(3-)` and `[Cu(CN)_(4)]^(2-)`
    D
    `[NiCl_(4)]^(2-)` and `[CoCl_(4)]^(2-)`

  • The best oxidant & non metal with the highest SRP value

    A
    `F_(2)`
    B
    `Cl_(2)`
    C
    `Br_(2)`
    D
    `I_(2)`

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