Silver atom has completely filled d-orbitals `(4d^(10))` in its ground state. How can you say that it is a transition element ?

Explanation

Silver (atomic no = 47), in its + 1 oxidation state exhibits `4d^(10)5s^(0)` configuration. But in some compounds it also shows + 2 oxidation state, i.e., `4d^(9)5s^(0)` configuration. Here d-orbital is not completely filled. Therefore, silver is a transition element.