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A circular coil of wire consisting of 10...

A circular coil of wire consisting of 100 turns, each of radius 8.0 cm carries a current of 0.40 A. What is the magnitude of the magnetic field B at the centre of the coil ?

Text Solution

Verified by Experts

Here, `n=100, r=8 cm =8xx10^(-2)m and I=0.40 A`
The magnetic field B at the centre
`B=(mu_(0))/(4pi).(2pi I n)/(r )=(10^(-7)xx2xx3.14xx0.4xx100)/(8xx10^(-2))=3.1xx10^(-4) T`
The direction of magnetic field depends on the direction of current if the direction of current is anticlockwise. According to Maxwell's right hand rule, the direction of magnetic field at the centre of coil will be perpendicular outwards to the plane of paper.
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Knowledge Check

  • A circular arc of wire subtends an angle pi /2 at the centre. If it carries a current i and its radius of curvature is R then the magnetic field at the centre of the arc is

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