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Given the mass of iron nucleus as 55.85 ...

Given the mass of iron nucleus as 55.85 u and A = 56, find the nuclear density ?

Text Solution

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`m_(Fe)=55.85, u = 9.27xx10^(-26)kg`
Nuclear density `= ("mass")/("volume")=`
`(9.27xx10^(-26))/((4pi//3)(1.2xx10^(-15))^(3))xx(1)/(56)`
`= 2.29xx10^(17)"kg m"^(-3)`
The density of matter in neutron stars (an astrophysical object) is comparable to this density. This shows that matter in these objects has been compressed to such an extent that they resemble a big nucleus.
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Knowledge Check

  • A nuclear af rest undergoes a decay emitting and alpha- particle of de-Broglie wavelength lamda=5.76xx10^(-15) meter. he mass of the daughter nucleus is 223.610 amu and that of the alpha - particle is 4.002 a.m.u. (1"amu"=931.470(MeV)/(C^(2))) The total kinetic energy of the system in the final state is ( m_(d) = mass of daughter nucleus) m_(alpha) = mass of alpha- particle

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