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The K(alpha) X-ray emission line of lung...

The `K_(alpha)` X-ray emission line of lungsten accurs at `lambda = 0.021 nm`. What is the energy difference between `K`and `L` levels in the atom?

Text Solution

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`Delta E = (hc)/(lambda) = (6.62 xx 10^(-34) xx 3 xx 10^(8))/(0.021 xx 10^(-9))`
`= 9.46 xx 10^(-15)J = 5.9 xx 10^(4) e V = 59 ke V`
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Knowledge Check

  • The K_(alpha) X -ray emission line of tungsten occurs at lambda = 0.021 nm . The energy difference between K and L levels in this aotm is about : 0.51 MeV

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    `0.51 MeV`
    B
    `1.2 MeV`
    C
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    D
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    B
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    D
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  • A The wavelength of the K_alpha line ofthe characteristic X rays emitted by an element is 0.64 Å . What is the wavelength of K_beta line emitted by the same element?

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    B
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