The two waves are represented by
`y_(1) 10^(-6) sin(100t (x)/(50) 0.5)m`
`Y_(2) 10^(-2) cos(100t (x)/(50))m`
where x is ihn metres and t in seconds. The phase difference between the waves is approximately:

Options

A. 1.07 rad
B. 2.07 rad
C. 0.5 rad
D. 1.5 rad

Answer

a

Explanation

`y_(1)=10^(-6)sin(100t+(x)/(50)+0.5)m`
`Y_(2)=10^(-2)cos(100t+(x)/(50))m`
`implies y_(2)=10^(-2)sin(100t+(x)/(50)+(pi)/(2))`
Phase difference`=(pi)/(2)-0.5`
`=1.07 rad`