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The two waves are represented by y(1) ...

The two waves are represented by
`y_(1) 10^(-6) sin(100t (x)/(50) 0.5)m`
`Y_(2) 10^(-2) cos(100t (x)/(50))m`
where x is ihn metres and t in seconds. The phase difference between the waves is approximately:

A

1.07 rad

B

2.07 rad

C

0.5 rad

D

1.5 rad

Text Solution

Verified by Experts

The correct Answer is:
a
`y_(1)=10^(-6)sin(100t+(x)/(50)+0.5)m`
`Y_(2)=10^(-2)cos(100t+(x)/(50))m`
`implies y_(2)=10^(-2)sin(100t+(x)/(50)+(pi)/(2))`
Phase difference`=(pi)/(2)-0.5`
`=1.07 rad`
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Knowledge Check

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