A wave equation which gives the displacement along the y-direction is given by `y = 10^(-4) sin(60t + 2x)` where `x and y` are in meters and `t` is time in seconds. This represents a wave

Options

A. Travelling with a velocity of `30 m//s` in the negative x-direction
B. or wavelength `pi` metres
C. of frequency `30//pi` Hertz
D. of amlitude `10^(-4)m` travelling along the negative x-direction

Answer

a., b., c.,d.

Explanation

`y=10^(-4) sin (60t+2x)`
`y=a sin(omegat+kx)`
Now, `k=2, 2pi//lambda=2 or lambda=pi metre`
Again, `omega =60`
or `2pif=60` or `f=(60)/(2pi)` or `v=(30)/(pi)Hz`
Again, `v=(omega)/(k)=(60)/(2) m//s=30 m//s`