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A rod of nickel of length l is clamped a...

A rod of nickel of length `l` is clamped at its midpoint . The rod is stuck and vibrations are set up in the rod . Find the general expression for the frequency of the longitudinal vibrations of the rod . Young's modulus and density of the rod is `Y and rho` , respectively.

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To find the general expression for the frequency of the longitudinal vibrations of a nickel rod clamped at its midpoint, we can follow these steps: ### Step 1: Understand the Setup The rod has a length \( L \) and is clamped at its midpoint. This means that the rod can vibrate in modes where there are nodes at the midpoint. ### Step 2: Determine the Wavelength for the Fundamental Mode For the fundamental mode of vibration in a rod clamped at its midpoint, the length of the rod \( L \) is equal to half the wavelength (\( \lambda_1 \)) of the fundamental frequency. Thus, we can write: \[ L = \frac{\lambda_1}{2} \] This implies: \[ \lambda_1 = 2L \] ### Step 3: Relate Frequency, Wavelength, and Wave Speed The speed of longitudinal waves in a rod is given by: \[ v = \sqrt{\frac{Y}{\rho}} \] where \( Y \) is the Young's modulus and \( \rho \) is the density of the rod. The relationship between speed, frequency, and wavelength is given by: \[ v = f \lambda \] For the fundamental frequency \( f_1 \): \[ v = f_1 \lambda_1 \] ### Step 4: Substitute for Wavelength Substituting \( \lambda_1 = 2L \) into the wave speed equation gives: \[ v = f_1 (2L) \] Thus, we can express the frequency as: \[ f_1 = \frac{v}{2L} \] ### Step 5: Substitute the Speed of Sound in the Rod Now, substituting the expression for \( v \): \[ f_1 = \frac{1}{2L} \sqrt{\frac{Y}{\rho}} \] ### Step 6: Generalize for Higher Modes For the \( n \)-th mode of vibration, the relationship changes. The general expression for the frequency of the \( n \)-th mode can be given by: \[ f_n = \frac{(2n-1)}{2L} \sqrt{\frac{Y}{\rho}} \] where \( n \) is a positive integer (1, 2, 3, ...). ### Final Expression Thus, the general expression for the frequency of the longitudinal vibrations of the rod is: \[ f_n = \frac{(2n-1)}{2L} \sqrt{\frac{Y}{\rho}} \]

To find the general expression for the frequency of the longitudinal vibrations of a nickel rod clamped at its midpoint, we can follow these steps: ### Step 1: Understand the Setup The rod has a length \( L \) and is clamped at its midpoint. This means that the rod can vibrate in modes where there are nodes at the midpoint. ### Step 2: Determine the Wavelength for the Fundamental Mode For the fundamental mode of vibration in a rod clamped at its midpoint, the length of the rod \( L \) is equal to half the wavelength (\( \lambda_1 \)) of the fundamental frequency. Thus, we can write: \[ ...
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Knowledge Check

  • A steel rod 100 cm long is clamped at its midpoint. The fundamental frequency of longitudinal vibrtions of the rod is 3 kHz. What is the speed of the sound in the rod?

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  • A steel rod of length 100 cm is clamped at the middle. The frequency of the fundamental mode for the longitudinal vibrations of the rod is (Speed of sound in steel = 5 km s^(-1) )

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