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The average power transmitted across a cross section by two sound waves moving in the same direction are equal. The wavelength of two sound waves are in the ratio of `1:2`, then find the ratio of their pressure amplitudes.

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Intensity is given bt `I=(p_0^2)/(2rhov)`.
Here v and `rho` are same for both. And also given that `I` is same for both. So pressure amplitude is also same for both
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Knowledge Check

  • two sound waves moves in the same direction .if the average power transmiitted across a cross - section by them are equal while their wavelengths are in the ratio of 1:2 . Their pressure amplitudes would be in the ratio of

    A
    1
    B
    2
    C
    4
    D
    `1/2`

  • The ratio of the intensities two waves is 1 : 9 The ratio of their amplitudes is

    A
    `3:1`
    B
    `1:3`
    C
    `1:9`
    D
    `9:1`

  • If the ratio of intensities of two waves is 1 : 25, then the ratio of their amplitudes will be

    A
    `1:25`
    B
    `5:1`
    C
    `26 : 24`
    D
    `1 : 5 `
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