An organic acid `(A)` reacts with concentrated `H_2 SO_4` to give a neutral oxide `(B)`, acidic oxide `(c)` and a diatomic oxide `(D)`. When `(D)` reacts with chlorine gas, a poisonous gas `( E)` is evolved. This gas with ammonia gives an organic compound `(F)`. The compound `(A)` and `(F)` are.

Options

A. `(A) = H_2 C_2 O_4` and `NH_2 CONH_2`
B. `(A) = CH_3 COOH` and `(F) = NH_2 CONH_2`.
C. `(A) = CHCl_3` and `(F) = H_2 C_2 O_4`
D. `(A) = C Cl_4` and `(F) = CH_3 CHO`.

Answer

A

Explanation

`underset("Organic compound")((A)) + underset("Conc") (H_(2) SO_(4)) overset(Delta)rarr underset("Neutral oxide") ((B)) + underset("Acidic oxide") ((C)) + underset("Diatomic oxide") ((D))`
`(D) + Cl_(2) rarr underset("Poisonous gas") (( E))`
`( E) + NH_(3) rarr underset("Organic compound") ((F))`
`overset(underset(|)("COOH"))overset("COOH")((A)) overset(Delta) underset(Conc. H_(2) SO_(4))rarr underset((B)) (H_(2) O) + underset((C)) (CO_(2)) +_ underset((D)) (CO)`
`H_(2) O (B)` is neutral oxide
`CO_(2) (c)` is acidic oxide
`CO (D)` is diatomic oxide
`underset((D))(CO) + Cl_(2) rarr COCl_(2)`
`COCl_(2) + NH_(3) rarr underset((F) "Urea") (NH_(2) CONH_(2))`
Hence `(A)` and `(F)` are `(COOH)_(2)` and `NH_(2) CONH_(2)` respectively.