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Transition metals and many of their comp...

Transition metals and many of their compounds show paramagnetic behaviour where there are unpaired electron or electrons. The magnetic moment arises from the spin and orbital motions in ions or molecule. Magnetic moment of n unpaired electrons is given as
`mu=sqrt(n(n+2))` Bohr magneton
Magnetic moment increases as the number of unpaired electrons increases.
Q. Increasing value of magnetic moment of
(I) `[Fe(CN)_6]^(4-)`
(II) `[Fe(CN)_6]^(3-)`,
(III) `[Cr(NH_3)_6]^(3+)`
(IV) `[Ni(H_2O)_4]^(2+)` is:

A

`IltIIltIIIltIV`

B

`IVltIIIltIIltI`

C

`IIltIIIltIltIV`

D

`IltIIltIVltIII`

Text Solution

Verified by Experts

The correct Answer is:
d
`{:("compound","unpaired"),(I,0),(II,1),(III,3),(IV,2):}`
Hence answer is (d) i.e., `IltIIltIVltIII`
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Knowledge Check

  • Transition metals and many of their compounds show paramagnetic behaviour where there are unpaired electron or electrons. The magnetic moment arises from the spin and orbital motions in ions or molecule. Magnetic moment of n unpaired electrons is given as mu=sqrt(n(n+2)) Bohr magneton Magnetic moment increases as the number of unpaired electrons increases. Q. In 3d series the maximum magnetic moment is shown by

    A
    Sc
    B
    V
    C
    Cr
    D
    Fe

  • Transition metals and many of their compounds show paramagnetic behaviour where there are unpaired electron or electrons. The magnetic moment arises from the spin and orbital motions in ions or molecule. Magnetic moment of n unpaired electrons is given as mu=sqrt(n(n+2)) Bohr magneton Magnetic moment increases as the number of unpaired electrons increases. Q. Which among the following ions has maximum value of magnetic moment

    A
    `Cu^(2+)`
    B
    `Mn^(2+)`
    C
    `Cr^(2+)`
    D
    `Ti^(2+)`

  • Transition metals and many of their compounds show paramagnetic behaviour where there are unpaired electron or electrons. The magnetic moment arises from the spin and orbital motions in ions or molecule. Magnetic moment of n unpaired electrons is given as mu=sqrt(n(n+2)) Bohr magneton Magnetic moment increases as the number of unpaired electrons increases. Q. Magnetic moment of [Ni(CN)_4]^(2-) is zero but that of [Ni(H_2O)_4]^(2+) is 2.83BM . is because of :

    A
    `CN^(ɵ)` is a strong ligand making two unpaired electrons in `Ni^(2+)` to pair up, while in `[Ni(H_2O)_4]^(2+)` two electrons remain unpaired as `H_2O` is a weak ligand.
    B
    Different oxidation state of `Ni` in two complexes
    C
    Both (a) and (b)
    D
    none of the above

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