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An aqueous solution containing one mole ...

An aqueous solution containing one mole of `HgI_2` and two moles of NaI is orange in colour. On addition of excess NaI the solution becomes colourless. The orange colour reappears on subsequent addition of NaOCl. Explain with equation.

Text Solution

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Sodium iodide on reaction with `Hgl_2` gives complex salt, `Na[HgI_4]`

Orange colour is due to presence of residual `Hgl_2`.
But on addition of excess NaI, it becomes colourless due to change of `Hgl_2` into `Na[HgI_4]`
`HgI_2+2NaI` (excess) `toNa_2[HgI_4]` (colourless)
The orange colour of `HgI_2` reappears due to conversion of `Na_2[HgI_4]` into `HgI_2` by means of `NaOCl`.
`3Na_2[HgI_4]+2NaOCl+2H_2Oto`
`3HgI_2+2NaCl+4NaOH+2NaI_3`
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An aqueous solution containing 1 mol of HgI_(2) and 2 mol of Nal is orange in colour .On addition od excess NaI , the solution becomes colourless .The orange colour reappears on subsequent addition of NaOCl .

An aqueous solution containing 1 mol of HgI_(2) and 2mol of Nal is orange in colour. On addition of excess NaI the solution becomes colourless The orange colour reappears on subsequent addition of Na OCI Explain with equations .

Knowledge Check

  • On addition of excess NaOH solution, which of the following will produce a coloured solution?

    A
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    B
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    C
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