Arrange the following compounds in the order of decreasing molar conductivity in aqueous solution.
`i.a. K[Co(NH_(3))_(2)(NO_(2))_(4)]`
`b. [Cr(NH_(3))_(3)(NO_(2))_(3)]`
`c." " [Cr(NH_(3))_(5)(NO_(2))]_(3)[Co(NO_(2))_(6)]_(2)`
`d." "[Mg(Cr(NH_(3)(NO_(2))_(5)]`
`ii. a. Li[Co(NH_(3))_(2)(NO_(2))_(4)]" "b." "Na[Co(NH_(3))_(2)(NO_(2))_(4)]`
` c.K[Co(NH_(3))_(2)(NO_(2))_(4)]" "d." "Cs[Co(NH_(3))_(2)(NO_(2))_(4)]`
`iii. a. Pt(NH_(3))_(6)Cl_(4)"" b." " Cr(NH_(3))_(6)Cl_(3)`
`c." " Co(NH_(3))_(4)Cl_(3)" "d. K_(2)PtCl_(6)`

Explanation

Since coordination number `(C.N)` of `Pt^(4+) =6`
`:.[Pt(NH_(3))_(6)]CI_(4)implies5ions`
(b) `CN` of `Cr^(3+) =6`
`:. [Cr(NH_(3))_(6)]CI_(3)implies4ions`
(c ) `CN` of `Co^(3+) =6`
`:.[Co(NH_(3))_(4)CI_(2)]implies2 ions`
(d) `K_(2)[PtCI_(6)]implies 3 ions`
Increasing order of conductane is
`cltdltblta` .