Home
Class 12
CHEMISTRY
How many geometrical isomers are possibl...

How many geometrical isomers are possible for the square planar complex `[Pt(NO_(2))(py)(NH_(3))(NH_(2)OH)]NO_(2)`
(a) `Four
(b) Five
(c ) Eight
(d) Three .

Text Solution

Verified by Experts

The correct Answer is:
d

It is `[Mabcd]^(n+-)` type complex which shows three isomers .
Promotional Banner

Topper's Solved these Questions

  • COORDINATION COMPOUNDS

    CENGAGE CHEMISTRY|Exercise Ex 7.2 Subjective|4 Videos
  • COORDINATION COMPOUNDS

    CENGAGE CHEMISTRY|Exercise Ex 7.2 Objective|8 Videos
  • COORDINATION COMPOUNDS

    CENGAGE CHEMISTRY|Exercise Ex 7.1 Objective (Terminology)|16 Videos
  • CHEMICAL KINETICS

    CENGAGE CHEMISTRY|Exercise Archives Subjective|23 Videos
  • D AND F BLOCK ELEMENTS

    CENGAGE CHEMISTRY|Exercise Archives Subjective|29 Videos

Similar Questions

Explore conceptually related problems

How many geometrical isomers are possible for the complex ion [Cr(NH_(3))(OH)_(2)CI_(3)]^(2-) .

How many geometrical isomers are possible for the [Ni(NH_(3))_(4)]^(2+) ?

Three geometrical isomers of the square planar complex [Pt(NH_(3)(H_(2)O)(py)(NO_(2))]^(+) are possible. What are they

The number of geometrical isomers possible for the complex [Pt(NH_(3))(NH_(2)OH)(py)Cl]^(+) is

The complex [Pt(py)(H_(2)O)(NH_(3))(NO_(2))ClBr] has :