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How many geometrical isomers are possibl...

How many geometrical isomers are possible for the square planar complex `[Pt(NO_(2))(py)(NH_(3))(NH_(2)OH)]NO_(2)`
(a) `Four
(b) Five
(c ) Eight
(d) Three .

Text Solution

Verified by Experts

The correct Answer is:
d
It is `[Mabcd]^(n+-)` type complex which shows three isomers .
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Knowledge Check

  • The complex [Pt(py)(H_(2)O)(NH_(3))(NO_(2))ClBr] has :

    A
    10 geometrical isomers, each one is optically active
    B
    10 geometrical isomers, five of them are optically active
    C
    15 geometrical isomers, each one is optically active
    D
    15 geometrical isomers, each one is optically inactive

  • The complex [Pt(py)(H_(2)O)(NH_(3))(NO_(2))ClBr] has :

    A
    10 geometrical isomers, each one is optically active
    B
    10 geometrical isomers, five of them are optically active
    C
    15 geometrical isomers, each one is optically active
    D
    15 geometrical isomers, each one is optically inactive

  • The number of geometrical isomers that can exist for square planar [Pt(Cl)(py)(NH_(3))(NH_(2)OH)]^(+) is (py = pyridine)

    A
    4
    B
    6
    C
    2
    D
    3

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