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Among ni(CO)(4),[Ni(CN)(4)]^(2-) and NiC...

Among `ni(CO)_(4),[Ni(CN)_(4)]^(2-)` and `NiCI_(4)^(2-)` .

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The correct Answer is:
c
`[Ni(CO)_(4)] OS Ni is 0`
`Ni = (Z =28) implies 3d^(8) 4s^(2)`
`CO` is a strong field ligand it causes pairing
`sp^(3)` Hybridisation(tetrahedral) There are no unpaired electrons, so the complex is diamagnetic Spin magnetic moment = zero
(ii) `[Ni(CN)_(4)]^(2-),Ni^(2+) =3d^(8)`
Cyano is strong field ligand, it causes pairing
`dsp^(2)` hybridisation (squareplanar) There are no unpaired electrons so the complex diamgnetic Spin magnetic moment = zero
(iii) `[NiCI_(4)]^(2-),Ni^(2+) = 3d^(8)`
Chlorido is a weak field no pairing `sp^(3)` hybridisation (tetrahedral) There are two unpaired electrons, so the complex is paramagnetic Spin magnetic moment
`mu =sqrt( n (n +2)) BM = sqrt(2(2 + 2)) BM =sqrt8 BM`


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