Statement I `[Fe(H_(2)O)_(5)NO]SO_(4)` is paramagnetic
Statement II The Fe in `[Fe(H_(2)O)_(5)NO]SO_(4)` has three unpaired electrons .

Answer

a

Explanation

`[Fe(H_(2)O)_(5)NO]SO_(4)`
`NO` has charge equal to `+1` in this complex Therefore, the oxidation number of Fe in the complex becomes `+1`
`Fe = 3d^(6) 4s^(2),Fe^(o+) =3d^(6) 4s^(1)`
Since `H_(2)O` is a weak filed ligand and `No^(o+)` is a strong field ligand so olny `NO^(o+)` cause pairing of `4s` electron Thus only one pairing occurs
Thus the configuration is `3d^(7)` and the complex of unpaired electrons is 3