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Why is K(a2)ltltK(a1) for H2SO4 in water...

Why is `K_(a_2)ltltK_(a_1)` for `H_2SO_4` in water?

Text Solution

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`H_2SO_4` ionises in two steps and hence has two dissociation constants, i.e., `H_2SO_4` acts as a dibasic acid.
(a). `H_2SO_4+H_2OtoHSO_4^(ɵ)+H_3O^(o+)` `K_(a_1)`
(b). `HSO_4^(ɵ)+H_2OtoSO_4^(2-)+H_2O^(o+)` `K_(a_2)`
`K_(a_1)ltK_(a_1)` because the negatively charged `HSO_4^(ɵ)` ion has much less tendency to donate a proton as compared to netural `H_2SO_4`.
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Knowledge Check

  • A : For H_2CO_3 K_(a_1) lt K_(a_2) . R : H_2CO_3 is weaker acid than HCO_3^-

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