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If pressure P, velocity V and time T are...

If pressure P, velocity V and time T are taken as fundamental physical quantities, the dimensional formula of force if

A

`PV^2T^2`

B

`P^-1V^2T^-2`

C

`PVT^2`

D

`P^-1VT^2`

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The correct Answer is:
To find the dimensional formula of force (F) when pressure (P), velocity (V), and time (T) are taken as fundamental quantities, we can follow these steps: ### Step 1: Write the relationship for force We start by expressing force in terms of the fundamental quantities: \[ F \propto P^X V^Y T^Z \] where \( X, Y, Z \) are unknown exponents that we need to determine. ### Step 2: Write the dimensional formulas We know the following dimensional formulas: - Force (F): \( [F] = M L T^{-2} \) - Pressure (P): \( [P] = \frac{F}{A} = \frac{M L T^{-2}}{L^2} = M L^{-1} T^{-2} \) - Velocity (V): \( [V] = \frac{L}{T} = L T^{-1} \) ### Step 3: Substitute the dimensional formulas Now we substitute the dimensional formulas into our expression: \[ F = K \cdot (M L^{-1} T^{-2})^X \cdot (L T^{-1})^Y \cdot (T)^Z \] ### Step 4: Expand the right-hand side Expanding the right-hand side gives: \[ F = K \cdot M^X \cdot L^{-X} \cdot T^{-2X} \cdot L^Y \cdot T^{-Y} \cdot T^Z \] Combining the terms: \[ F = K \cdot M^X \cdot L^{Y - X} \cdot T^{-2X - Y + Z} \] ### Step 5: Set up equations by comparing dimensions Now we can compare the dimensions of both sides: 1. For mass (M): \( X = 1 \) 2. For length (L): \( Y - X = 1 \) 3. For time (T): \( -2X - Y + Z = -2 \) ### Step 6: Solve the equations From the first equation, we have: - \( X = 1 \) Substituting \( X = 1 \) into the second equation: - \( Y - 1 = 1 \) → \( Y = 2 \) Substituting \( X = 1 \) and \( Y = 2 \) into the third equation: - \( -2(1) - 2 + Z = -2 \) - \( -2 - 2 + Z = -2 \) - \( Z = 2 \) ### Step 7: Write the final expression for force Now we can write the expression for force: \[ F = K \cdot P^1 \cdot V^2 \cdot T^2 \] Thus, the dimensional formula for force is: \[ F = P V^2 T^2 \] ### Conclusion The dimensional formula of force when pressure, velocity, and time are taken as fundamental quantities is: \[ F = P V^2 T^2 \]

To find the dimensional formula of force (F) when pressure (P), velocity (V), and time (T) are taken as fundamental quantities, we can follow these steps: ### Step 1: Write the relationship for force We start by expressing force in terms of the fundamental quantities: \[ F \propto P^X V^Y T^Z \] where \( X, Y, Z \) are unknown exponents that we need to determine. ### Step 2: Write the dimensional formulas ...
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Knowledge Check

  • If energy E , velocity v and time T are taken as fundamental quanties, the dimensional formula for surface tension is

    A
    `[Ev^(-2) T^(-2)]`
    B
    `[E^(2) vT^(-2)]`
    C
    `[Ev^(-2) T^(-1)]`
    D
    `[E^(-2) v^(-2) T^(-1)]`
  • If the mass time and work are taken as fundamental physical quantities then dimensional formula of length

    A
    `[m^(1/2)T^(1)W^(-1/2)]`
    B
    `[M^(-1/2)T^(1)W^(1/2)]`
    C
    `[M^(-1)T^(2)W]`
    D
    none of these
  • If energy (E ) , velocity (V) and time (T) are chosen as the fundamental quantities , the dimensions formula of surface tension will be

    A
    `[EV^(-2)T^(-1)]`
    B
    `[EV^(-1)T^(-2)]`
    C
    `[EV^(-2)T^(-2)]`
    D
    `[E^(-2)V^(-1)T^(-3)]`
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