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If a particle starts moving along a stra...

If a particle starts moving along a straight ine withinitial velocity u under contact acceleration a, its displacement with time is given by the relation `x=ut+(1)/(2)at^2`
Q. Differentiation of `x` w.r.t. `t` will be

A

`y=(at)/(2)`

B

`u+at`

C

`u+2at`

D

`(ut^2)/(2)+(at^3)/(6)`

Text Solution

Verified by Experts

The correct Answer is:
B
`x=ut+(1)/(2)at^2`
`dx=u(1)+(1)/(2)a(2t)=u+at`
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Knowledge Check

  • If a particle starts moving along a straight ine withinitial velocity u under contact acceleration a, its displacement with time is given by the relation x=ut+(1)/(2)at^2 Q. The concerned deviation of positon time realtion w.r.t will be. Differentiation of above result w.r.t. t will be

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    none

  • Differentiation of sin(x^2) w.r.t. x is

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    `2xcos(x^2)`
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    `x^2cos(x^2)`
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    `-cos(2x)`

  • Differentiation of sin(x^(2)+3)w.r.t.x is-

    A
    `cos(x^(2)+3)`
    B
    `2x cos(x^(2)+3)`
    C
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