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The refractive index mu of a medium is f...

The refractive index `mu` of a medium is found to vary with wavelength `lambda` as `mu = A +(B)/(lambda^2).` What are the dimensions of A and B?

Text Solution

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mu = `("velocity of light in vacuum")/("velocity of light in medium")`
`= "dimensionless number" `
A`mu = A +(B)/(lambda^2),therefore`, A must be
dimensionless, and `B = mu lambda^2 = [L^2]`
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Knowledge Check

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    temperature of the medium
    B
    wavelength of the incident light
    C
    nature and physical state of the medium
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    `[M^(0)L^(0)T^(0)][M^(0)L^(2)T^(-1)]`
    B
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