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In the experiment to determine Young's m...

In the experiment to determine Young's modulus of the material of a wire under tension
used in the arrangement as shown. The percentage error in the measurement
of length is `a` in the measurement of the radius of the wire is `b` and in the
measurement of the change in length of the wire is `c`. Percentage error in the measurement
of Young's modulus for a given load is

A

`a-2 b+c`

B

`a-2 b-c`

C

`a+2 b+c`

D

`a+2 b`

Text Solution

Verified by Experts

The correct Answer is:
C

`Y =(F)/(pi r^(2))xx(l)/(Delta l)`
Taking log of both the sides
`log Y = log F + log l - log pi - 2 log r - log Delta l`
Differentiating it, we have
`(Delta Y)/(Y)=0 +(Delta l)/(l) - 0 -(2Delta r)/(r) - (Delta l)/(Delta l)`
% error, `(Delta Y)/(Y)xx100= ((Delta l)/(l) + (2Delta r)/(r) + (Delta(Delta l))/(Delta l))xx100`
`=a + 2b + c`
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Knowledge Check

  • The Young's modulus of the material of a wire is equal ot the

    A
    stress required to increase its length four times
    B
    stress required to produce unit strain
    C
    strain produced in it
    D
    half the strain produced in it
  • As temperture increases the Young's modulus of the material of a wire

    A
    increases
    B
    decreases
    C
    remains the same
    D
    becomes infinite
  • The percentage error in the measurement of the voltage V is 3% and in the measurement of the current is 2%. The percentage error in the measurement of the resistance is

    A
    `3%`
    B
    `2%`
    C
    `1%`
    D
    `5%`
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