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In Vander Wall's equation (P +(a)/(V^2))...

In Vander Wall's equation `(P +(a)/(V^2))(V - b) = RT` What are the dimensions of a and b ? Here, P is pressure, V is volume, T is temperature and R is gas constant.

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To find the dimensions of \(a\) and \(b\) in the Van der Waals equation \((P + \frac{a}{V^2})(V - b) = RT\), we need to analyze the equation dimensionally. ### Step-by-Step Solution: 1. **Identify the dimensions of pressure \(P\):** \[ [P] = \text{Pressure} = \frac{\text{Force}}{\text{Area}} = \frac{MLT^{-2}}{L^2} = ML^{-1}T^{-2} \] ...
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Knowledge Check

  • In equation (P+(a)/(V^(2)))(V-b)=RT , the dimensional formula of a is

    A
    `[ML^(3)T^(-2)]`
    B
    `[ML^(-5)T^(-2)]`
    C
    `[ML^(5)T^(-2)]`
    D
    `[ML^(2)T^(-2)]`
  • In the equation (P+(a)/(V^(2)))(V-b) = RT ,, the SI unit of a is

    A
    `Nm^(2)`
    B
    `Nm^(4)`
    C
    `Nm^(-3)`
    D
    `Nm^(-2)`
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