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The value of Stefan's constant is sigma ...

The value of Stefan's constant is `sigma =5.76xx 10^(-8) J s^(-1) m^(-2)K^(-4).` Find its value in cgs system.

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To convert Stefan's constant from the SI system (MKS) to the CGS system, we need to follow these steps: ### Step 1: Write down the given value of Stefan's constant in SI units. The value of Stefan's constant is given as: \[ \sigma = 5.76 \times 10^{-8} \, \text{J s}^{-1} \text{m}^{-2} \text{K}^{-4} \] ### Step 2: Convert the units from SI to CGS. In the CGS system, the units are as follows: - 1 Joule (J) = \(10^7\) ergs - 1 meter (m) = \(10^2\) centimeters (cm) - Temperature (Kelvin) remains the same in both systems. ### Step 3: Substitute the unit conversions into the equation. We need to convert the units in the expression for \(\sigma\): \[ \sigma = 5.76 \times 10^{-8} \, \text{J s}^{-1} \text{m}^{-2} \text{K}^{-4} = 5.76 \times 10^{-8} \, \text{J} \cdot \text{s}^{-1} \cdot \text{m}^{-2} \cdot \text{K}^{-4} \] Substituting the conversions: \[ = 5.76 \times 10^{-8} \cdot (10^7 \, \text{erg}) \cdot \text{s}^{-1} \cdot (10^{-2} \, \text{cm})^{-2} \cdot \text{K}^{-4} \] ### Step 4: Simplify the expression. Now we simplify the expression: \[ = 5.76 \times 10^{-8} \cdot 10^7 \cdot \text{s}^{-1} \cdot 10^{-4} \, \text{cm}^{-2} \cdot \text{K}^{-4} \] \[ = 5.76 \times 10^{-8 + 7 - 4} \, \text{erg s}^{-1} \text{cm}^{-2} \text{K}^{-4} \] \[ = 5.76 \times 10^{-5} \, \text{erg s}^{-1} \text{cm}^{-2} \text{K}^{-4} \] ### Step 5: Final result. Thus, the value of Stefan's constant in the CGS system is: \[ \sigma = 5.76 \times 10^{-5} \, \text{erg s}^{-1} \text{cm}^{-2} \text{K}^{-4} \] ---

To convert Stefan's constant from the SI system (MKS) to the CGS system, we need to follow these steps: ### Step 1: Write down the given value of Stefan's constant in SI units. The value of Stefan's constant is given as: \[ \sigma = 5.76 \times 10^{-8} \, \text{J s}^{-1} \text{m}^{-2} \text{K}^{-4} \] ...
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The value of Stefan's constant is sigma = 5.67xx10^(-8)Js^(-1)m^(2)K^(-4) . Find its value in CGS system, where joule (J) and erg are the units of energy in SI and CGS system, respectively.

Stefan’s contain (s) derives from other known con- stant of nature, viz. Boltzmann constant, (k) planck’s con- stant (h) and speed of light in vacuum (c). Value of the constant is sigma=5.67xx10^(-8)Js^(-1)m^(-2)K^(-4) If speed of light were 2% more than its present value, how much different (in percentage) the value of sigma would have been?

Knowledge Check

  • A thin square steel plate with each side equal to 10 cm is heated by a blacksmith. The rate of radiated energy by the heated plate is 1134 W . The temperature of the hot steel plate is (Stefan's constant sigma = 5.67 xx10^(-8) " watt "m^(-2) K^(-4) , emissivity of the plate = 1)

    A
    1000 K
    B
    1189 K
    C
    2000 K
    D
    2378 K
  • A metallic sphere having radius 0.08 m and mass m = 10 kg is heated to a temperature of 227^(@)C and suspended inside a box whose walls ae at a temperature of 27^(@)C . The maximum rate at which its temperature will fall is:- (Take e =1 , Stefan's constant sigma = 5.8 xx 10^(-8) W//m^(-2)K^(-4) and specific heat of the metal s = 90 cal//kg//deg J = 4.2 "Joules"//"Calorie")

    A
    `0.55^(@)C//sec`
    B
    `0.66^(@)C//sec`
    C
    `0.44^(@)C//sec`
    D
    `0.03^(@)C//sec`
  • The value fo universal gravitationla constant G in CGS system is 6.67xx10^(-8) dyne cm^(2) g^(-2) . Its value in SI system is

    A
    `6.67xx10^(-11) Nm^(2) kg^(-2)`
    B
    `6.67xx10^(-5) Nm^(2) kg^(-2)`
    C
    `6.67xx10^(-10) Nm^(2) kg^(-2)`
    D
    `6.67xx10^(-9) Nm^(2) kg^(-2)`
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    G = 6.67 xx 10^(-11) kg^(-1) m^(3) s^(-2) . Convert it into CGS system.

    The value of universal gravitational constant is 6.67xx10^(-8) "dyne" g^(-2) cm^2. What is its value in Mks system?

    An electric bulb with a tungsten filament has an area of 0.20 cm^2 and is raised to a temperature of the bulb to 3000 K emissivity of the filament is 0.40 and Stefan's constant is 5.7 xx 10^(-5) erg s^(-1) cm^(-1) K^(-4) . The electrical energy consumed by the bulb is E_1 watt. If due to fall in voltage, the temperature of the filament falls to 2800 K, then the wattage of the bulb is E_2 watt. Calculate the value of E_1 - E_2 , close to nearest integer.

    A metallic sphere having radius 0.08 m and mass m = 10kg is heated to a temperature of 227^(@)C and suspended inside a box whose walls are at a temperature of 27^(@)C . The maximum rate at which its temperature will fall is :- (Take e = 1, Stefan's constant sigma=5.8xx10^(-5)Wm^(-2)K^(-4) and specific heat of the metal s = 90 cal/kg/deg J = 4.2 Joules/Calorie)