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From a uniform circular disc of radius R...

From a uniform circular disc of radius `R`, a circular disc of radius `R//6` and having centre at a distance `R//2` from the centre of the disc is removed. Determine the centre of mass of remaining portion of the disc.

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To determine the center of mass of the remaining portion of the disc after removing a smaller disc, we can follow these steps: ### Step 1: Define the Problem We have a uniform circular disc of radius \( R \) and we are removing a smaller disc of radius \( \frac{R}{6} \) which is located at a distance \( \frac{R}{2} \) from the center of the larger disc. ### Step 2: Calculate the Masses 1. **Mass of the larger disc (M1)**: The area of the larger disc is \( A_1 = \pi R^2 \). Assuming uniform density \( \sigma \) (mass per unit area), the mass \( M_1 \) is given by: ...
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From a uniform circular disc of diameter d,a circular disc of diameter d//6 and having centre at a distance d//4 from the centre of the disc is scooped out. Determine the centre of mass of remaining portion.

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Knowledge Check

  • A circular hole of raidus 1 cm is cut off from a disc of radius 6 cm. The centreof the hole is 3 cm from the centre of the disc. Then the distance of the centre of mass of the remaining disc from the centre of the disc is

    A
    `3/35 cm`
    B
    `1/35cm`
    C
    `3/10cm`
    D
    None of these
  • From a circular disc of radius R , a triangular portion is cut (sec figure). The distance of the centre of mass of the remainder from the centre of the disc is -

    A
    `(4R)/(3(pi-2))`
    B
    `(2R)/(3(pi-2))`
    C
    `(5R)/(7(pi-2))`
    D
    `(R)/(3(pi-1))`
  • A circular hole is cut from a disc of radius 6 cm in such a way that the radius of the hole is 1 cm and the centre of 3 cm from the centre of the disc. The distance of the centre of mass of the remaining part from the centre of the original disc is

    A
    3/35 cm
    B
    1/35 cm
    C
    3/10 cm
    D
    7/35 cm
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