Home
Class 12
CHEMISTRY
Statement 1: The product (B) formed will...


Statement 1: The product `(B)` formed will be a racemic mixture.
Statement 2: The above reaction is oxymercuration and demercuration, and it proceeds via the addition of `D_(2)O`, according to Markovnikov's rule, and with antiregiospecificity.

Doubtnut Promotions Banner Mobile Dark

Text Solution

Verified by Experts

The correct Answer is:
A
The reactant `(A)` is trans. Oxymercuration and demercuation take place by anti-mechanism, so the product `(B)` would be racemic [trans reactant (with two same group) + anti (trans) mechanism of reagent `rarr` Racemic product]. Both the statements `1` and `2` are true, so the answer is `(a)`.
|

Topper's Solved these Questions

  • REDUCTION AND OXIDATION REACTION OF ORGANIC COMPOUNDS

    CENGAGE CHEMISTRY|Exercise Exercise Archives (Subjective)|26 Videos

  • REDUCTION AND OXIDATION REACTION OF ORGANIC COMPOUNDS

    CENGAGE CHEMISTRY|Exercise SUBJECTIVE TYPE|3 Videos

  • REDUCTION AND OXIDATION REACTION OF ORGANIC COMPOUNDS

    CENGAGE CHEMISTRY|Exercise Exercise (Single Correct)|90 Videos

  • QUALITATIVE INORGANIC SALT ANALYSIS

    CENGAGE CHEMISTRY|Exercise Viva Voce Questions And Part-C (Analysis Of Cations)|42 Videos

  • SOLID STATE

    CENGAGE CHEMISTRY|Exercise Ex 1.2 (Objective)|9 Videos

Similar Questions

Explore conceptually related problems

Which is the wrong statement about oxymercuration `-` demercuration `?`

Which statement is true ? i . The product is ii. The product is iii. The reaction is called alkoxymercuration - demercuration ( a type of solvomercuration - demercuration ) . iv It proceeds via markovnikov addition addition, anti - addition of and ROH( a nucleophilc solvent ) and not rearrangement.

Statement 1: The product formed is (B). Statement 2: The reaction proceeds via the formation of the following species in the order: Radical anion rarr Vinylic anion rarr Vinylic redical rarr Product

Statement-1 : Statement-2 : Reaction proceeds via inversion configuration in SN_(2)

Which is/are correct statements about oxymercuration demercuration?

In which of the following reactions, addition does not occur according to Markovnikov's rule?

(A) : Reaction of 1-butene with HBr gives 1-bromobutane as major product
(R ) : Addition of hydrogen halides to alkenes proceeds according to Markovnikov's rule

In which of the following halogen addition reactions, racemic mixture of products is formed?

In which reaction addition takes place according to Markovnikov's rule:

Predict the major products (A) and (B) (OMDM is oxymercuration demercuration)

Oxymercuration-Demercuration (OMDM) reaction

Acid catalysed hydration of alkene gives alcohol. In this reaction addition of water takes place according to Markownikoff's rule. Since intermediate carbocation is formed in this reaction, rearrangement of carbocation takes place. In oxymercuration-demercuration reaction hydration of alkene takes place according to Markownikoff's rule. Oxymercuration demercuration is a better process than the catalytic hydration of alkene because in oxymercuration-demercuration, no rearrangement is possible. In hydroboration oxidation, hydration of alkene takes place as if it is according to anti-Markownikoff's addition. In hydroboration oxidation reaction rearrangement is not possible. Both in oxymercuration-demercuration and hydroboration oxidation intermediate carbocation are not formed. 2-phenyl propene on acidic hydration gives

Home
Profile