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Calculate the resonance enegry of N(2)O ...

Calculate the resonance enegry of `N_(2)O` form the following data
`Delta_(f)H^(Theta) of N_(2)O = 82 kJ mol^(-1)`
Bond enegry of `N-=N, N=N, O=O,` and `N=O` bond is `946, 418, 498`, and `607 kJ mol^(-1)`, respectively.

Text Solution

Verified by Experts

For `N_(2)O,N_(2)+(1)/(2)O_(2) rarr N_(2)O, DeltaH_(exp)=82kJ`
Also from bond energy data, using `N=N=O` structure for `N_(2)O`
`DeltaH_(f cal. ) =-[1(N=N)+1(N=O)]+[(N-=N)+(1)/(2)(O=O)]`
`-[418+607]+[946+(1)/(2)(498)]=+170kJ`
Now resonance energy
`=Exp .DeltaH_(f N_(2)O)-`Calcu lated `DeltaH_(f N_(2)O)`
`=82-170=-88kJ mol^(-1)`
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Calcualate the resonance energy of N_(2)O from the following data : Delta_(f)H^(@) of N_(2)O= 82kJ mol^(-1) , Bond energies of N -= N , N = N , O=O and N=O bonds are 946, 418, 498 and 607 kJ mol^(-1) respectively.

Calculate the resonance energy of N_(2)O from the following data : DeltaH_(f)^(@) of N_(2)O = 82 kJ mol^(-1) , Bond energies of N equivN , N = N , O =O and N =O bonds are 946, 418, 498 and 607 kJ mol^(-1) respectively.

Knowledge Check

  • Given that (i) Delta_(f)H^(@) of N_(2)O is 82kJ"mol"^(-1) (ii) Bond energies of N-=N,N=N,O=O and N=O are 946, 418, 498 and 607kJ"mol"^(-1) respectively, Th resoance energy of N_(2)O is

    A
    `-88kJ`
    B
    `-66kJ`
    C
    `-62kJ`
    D
    `-44kJ`

  • Calculate the resonance energy of N_2O from the following data, Delta_fH ofN_2O is 82KJ mol^(-1)N-=N,946 KJ mol^(-1),N=N,418KJ mol^(-1), 0 = 0 , 498 KJ mol^(-1), N = 0,607KJ mol^(-1)

    A
    `+8.85 " KJ mol"^(-1)`
    B
    `-88 " KJ mol"^(-1)`
    C
    `-8.8 " KJ mol"^(-1)`
    D
    `+88 " KJ mol"^(-1)`

  • calculateth resonance energy of N_(2)O Delta_(f)H^(-) of N_(2)O = 82 kJ mol ^(-1) bond energy of N=O = 607 kJmol ^(-1) bond energy of O=O = 498 kJ mol ^(-1) nond energy of N = N = 418 kJ mol^(-1) bond energy of N= N = 946 kJ mol ^(-1)

    A
    `82 kJ mol ^(-1)`
    B
    `-88 kJ mol ^(-1)`
    C
    `- 82 kJ mol ^(-1)`
    D
    `+ 88 kJ mol ^(-1)`

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    Calculate the resonance energy of N_(2)O from the following data : DeltaH_(f)^(0) "of" N_(2)O=82 kJ "mole"^(-1) Bond energies of N-=N, N=N,O=O and N=O bonds are 946, 418, 498 and 607 kJ "mole"^(-1) respectively.

    Calculate the resonance energy of N_(2)O from the following data: DeltaH_(1)^(@) of N_(2)O = 82 kJ "mole"^(-1) . Bond energies N=N = 946 kJ "mole"^(-1) N=N = 418 kJ "mole"^(-1) O=O = 498 kJ "mole"^(-1) N=O = 607 kJ "mol"^(-1)

    Calculate the resonance energy of N_(2)O from the following data: DeltaH_(1)^(@) of N_(2)O = 82 kJ "mole"^(-1) . Bond energies N=N = 946 kJ "mole"^(-1) N=N = 418 kJ "mole"^(-1) O=O = 498 kJ "mole"^(-1) N=O = 607 kJ "mole"^(-1)

    Calculate the resonance enegry of NO_(2) ( :O-N=O: ) The measured enthalpy formation of NO_(2)(Delta_(f)H^(Theta)) is 34 kJ mol^(-1) . The bond energies given are: N -O rArr 222 kJ mol^(-1) N -= N rArr 946 kJ mol^(-1) O = O rArr 498 kJ mol^(-1) N = O rArr 607 kJ mol^(-1)

    Use the given data to calculate the resonance energy of N_(2)O.(Delta_(f)H^(ө) of N_(2)O=82kJmol^(-1)) Bond energy of N=O to607kJmol^(-1) Bond energy of O=O to498kJmol^(-1) bond energy of N=N to418kJmol^(-1) Bond energy of N-=Nto946kJmol^(-1) Choose the correct option.

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