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Statement Oxidation number of Cu in CuH ...

Statement Oxidation number of `Cu` in `CuH` is -`1`
Explanation `Cu` is placed below `H` in electro-chemical series.

A

`S` is correct but `E` is wrong.

B

`S` is wrong but `E` is correct.

C

Both `S` and `E` are correct and `E` is correct explanation of `S`

D

Both `S` and `E` are correct but `E` is not correct explanation of `S`.

Text Solution

Verified by Experts

The correct Answer is:
C
Explanation is correct reason for statement.
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Assertion : Cu react with HCl & form H_(2) gas Reason : Cu above then hydrogen in electro chemical series

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Knowledge Check

  • Statement Oxidation state of H is +1 in CuH_(2) and -1 in CaH_(2) Explanation Ca is strong electropositve metal.

    A
    `S` is correct but `E` is wrong.
    B
    `S` is wrong but `E` is correct.
    C
    Both `S` and `E` are correct and `E` is correct explanation of `S`
    D
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  • Statement Oxidation number of metals in metal carbonyls is zero. Explanation The oxidation number of CO has been taken to be zero.

    A
    `S` is correct but `E` is wrong.
    B
    `S` is wrong but `E` is correct.
    C
    Both `S` and `E` are correct and `E` is correct explanation of `S`
    D
    Both `S` and `E` are correct but `E` is not correct explanation of `S`.

  • Coordination number of Cu^(2+) in CuSO_(4).5H_(2)O is .

    A
    5
    B
    4
    C
    3
    D
    2

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    The coordination number of Cu in complex [Cu(H_2O)_4]^(++) is

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    The coordination number of Cu in complex [Cu(H_(2)O)_(4)]^(++) is

    (A) Oxidation state of 'H' is +1 in CuH_(2) and is -1 "in" CaH_(2) (R ) Ca is stronger electropositive than hydrogen.

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