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Two roots of quadratic equations are giv...

Two roots of quadratic equations are given, frame the equation.
10 and -10

Text Solution

Verified by Experts

The correct Answer is:
`x^(2)-100=0` is the required quadratic equation.
Let `alpha=10andbeta=-10`
Then `alpha+beta=10-10=0`
`alphabeta=10xx(-10)=-100`
The required quadratic equation is
`x^(2)-(alpha+beta)x+alphabeta=0`
i.e. `x^(2)-(0)x-100=0`
i.e. `x^(2)-100=0`
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Knowledge Check

  • The roots of a quadratic equation are 5 and -2 . Then, the equation is

    A
    `x^(2)-3x+10=0`
    B
    `x^(2)-3x-10=0`
    C
    `x^(2)+3x-10=0`
    D
    `x^(2)+3x+10=0`

  • The two roots of a quadratic equation are given as x =(1)/(7) and x = (-1)/(8) The equation can be written as:

    A
    (7x-1)(8x - 1) = 0
    B
    (7x-1)(8x + 1) = 0
    C
    (7x + 1)(8x - 1) = 0
    D
    (7x + 1)(8x + 1) = 0

  • Number of roots the quadratic equation have

    A
    1
    B
    2
    C
    3
    D
    None of these

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