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In triangle ABC , angle ACB = 90^(...

In ` triangle ` ABC ,
` angle ACB = 90^(@)` ,
` CD bot AB` and
` DE bot CB`
Prove that ` CD^(2) xxAC = AD xx AB xxDE ` .

Answer

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Knowledge Check

  • In a triangle ABC ,AB = AC and AD bot BC , then :

    A
    `ABltAD`
    B
    `ABgtAD`
    C
    AB=AD
    D
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  • In a right triangle ABC, in which angleC = 90^@ amd CD bot AB. If BC =a, CA=b, AB=c and CD=p, then

    A
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    B
    `1/p^(2) ne 1/a^(2)+ 1/b^(2)`
    C
    `1/p^(2) lt 1/a^(2) +1/b^(2)`
    D
    `1/p^(2) gt 1/a^(2) +1/b^(2)`

  • In Delta ABC, angle B = 90^(@) and BD bot AC . If AC = 9 cm and AD = 3 cm, then BD is equal to :

    A
    `2 sqrt (2)` cm
    B
    `3 sqrt(2)` cm
    C
    `2 sqrt(3)` cm
    D
    `3 sqrt(3)` cm

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    In the given figure, angle ACB=90^(@) and CD bot AB . Prove that CD^(2)=BD*AD

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