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Two unlike charges of magnitude q are se...

Two unlike charges of magnitude `q` are separated by a distance `2d`. The potential at a point midway between them is

A

Zero

B

`(1)/(4pi epsilon_(0))`

C

`(1)/(4pi epsilon_(0)).(q)/(d)`

D

`(1)/(4pi epsilon_(0)).(2q)/(d^(2))`

Text Solution

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The correct Answer is:
To find the electric potential at a point midway between two unlike charges of magnitude \( q \) separated by a distance \( 2d \), we can follow these steps: ### Step 1: Identify the Charges and Their Positions Let’s denote the two charges as \( +q \) and \( -q \). Place the positive charge \( +q \) at position \( A \) and the negative charge \( -q \) at position \( B \). The distance between the two charges is \( 2d \). - Position of \( +q \) (Charge 1): \( A \) (let's say at \( x = -d \)) - Position of \( -q \) (Charge 2): \( B \) (let's say at \( x = +d \)) ### Step 2: Determine the Midpoint The midpoint \( P \) between the two charges is located at \( x = 0 \). The distance from the midpoint to each charge is \( d \). ### Step 3: Calculate the Potential Due to Each Charge The electric potential \( V \) due to a point charge is given by the formula: \[ V = \frac{k \cdot q}{r} \] where \( k \) is Coulomb's constant, \( q \) is the charge, and \( r \) is the distance from the charge to the point where the potential is being calculated. - **Potential at point \( P \) due to charge \( +q \)**: \[ V_1 = \frac{k \cdot (+q)}{d} \] - **Potential at point \( P \) due to charge \( -q \)**: \[ V_2 = \frac{k \cdot (-q)}{d} \] ### Step 4: Calculate the Total Potential at the Midpoint The total electric potential \( V \) at point \( P \) is the algebraic sum of the potentials due to both charges: \[ V = V_1 + V_2 \] Substituting the values we calculated: \[ V = \frac{k \cdot (+q)}{d} + \frac{k \cdot (-q)}{d} \] \[ V = \frac{kq}{d} - \frac{kq}{d} \] \[ V = 0 \] ### Conclusion The electric potential at the midpoint between the two unlike charges is \( 0 \). ---

To find the electric potential at a point midway between two unlike charges of magnitude \( q \) separated by a distance \( 2d \), we can follow these steps: ### Step 1: Identify the Charges and Their Positions Let’s denote the two charges as \( +q \) and \( -q \). Place the positive charge \( +q \) at position \( A \) and the negative charge \( -q \) at position \( B \). The distance between the two charges is \( 2d \). - Position of \( +q \) (Charge 1): \( A \) (let's say at \( x = -d \)) - Position of \( -q \) (Charge 2): \( B \) (let's say at \( x = +d \)) ...
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Knowledge Check

  • Two point charges Q and - Q //4 are separated by a distance X . Then .

    A
    potential is zero at a point on the axis which is ` x//3` on the right side of the cahrge `-q//4`
    B
    potential is zero at a point on the axis which is `x//5` on the left side fo the charge `- Q//4`
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    there exist two points on the axis where electric field is zero.
  • Two cahrges of 50muC and 100muC are separated by a distance of 0.6m .The intensity of electric filed at a point midway between them is

    A
    `50xx10^(6)v//M`
    B
    `5xx10^(6)M//V`
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  • Two bodies of masses M_(1) and M_(2) are kept separeated by a distance d. The potential at the point where the gravitational field produced by them is zero, is :-

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    B
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    C
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    D
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