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The charge on 500 c c of water due to pr...

The charge on `500 c c` of water due to protons will be

A

`6.0xx10^(27)C`

B

`2.67xx10^(7)C`

C

`6xx10^(23)C`

D

`1.67xx10^(23)C`

Text Solution

Verified by Experts

The correct Answer is:
b
`Q= n e`, where `n=` number of moles `xx6.02xx10^(23)xx10`
`implies Q=(500)/(18)xx6.02xx10^(23)xx10xx1.6xx10^(-19)`
`= 2.67xx10^(7)C`
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Knowledge Check

  • The distance between a proton and electron both having a charge 1.6xx10^(-19)C of a hydrogen atom is 10^(-12) metre .The value of intensity of electric field produced on electron due in proton will be

    A
    `14.4xx10^(14)N//C`
    B
    `12.2xx10^(14)N//C`
    C
    `11.4xx10^(14)N//C`
    D
    `13.2xx10^(14)N//C`

  • The correct order of acidity of the C-H proton is-

    A
    acetylene `gt` ethylene `gt` ethane
    B
    ethylene `gt` ethylene `gt` ethane
    C
    ethane `gt` ethylene `gt` acetylene
    D
    acetylene `gt` ethane `gt` ethylene

  • The ratio of specific charge of an electron to that of a protons is

    A
    `1:1`
    B
    ` 1837:1`
    C
    `1:1837`
    D
    `2:1`
    • A2Z-ELECTRIC CHARGE, FIELD & FLUX-Section D - Chapter End Test
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