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An electron moving in a circular orbit...

An electron moving in a circular orbit of radius `r` makes `n` rotation per second. The magnetic field produced at the centre has magnitude

A

`(mu_(0)"ne")/(2pi r)`

B

zero

C

`(mu_(0) n^(2) e)/(r)`

D

`(mu_(0)"ne")/(2r)`

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To find the magnetic field produced at the center of a circular orbit by an electron moving in that orbit, we can follow these steps: ### Step 1: Understand the problem We know that an electron is moving in a circular orbit of radius \( r \) and makes \( n \) rotations per second. We need to calculate the magnetic field at the center of this orbit. ### Step 2: Determine the current The current \( I \) produced by the moving charge can be calculated using the formula: \[ I = \frac{q}{T} \] where \( q \) is the charge and \( T \) is the time period for one complete rotation. Since the electron makes \( n \) rotations per second, the time period \( T \) is given by: \[ T = \frac{1}{n} \] Thus, the current can be expressed as: \[ I = q \cdot n \] ### Step 3: Substitute the charge of the electron The charge of an electron \( q \) is approximately \( e = 1.6 \times 10^{-19} \) C. Therefore, the current becomes: \[ I = n \cdot e \] ### Step 4: Use the formula for magnetic field The magnetic field \( B \) at the center of a circular loop carrying current \( I \) is given by the formula: \[ B = \frac{\mu_0 I}{2r} \] where \( \mu_0 \) is the permeability of free space, approximately \( 4\pi \times 10^{-7} \, \text{T m/A} \). ### Step 5: Substitute the expression for current into the magnetic field formula Now, substituting \( I = n \cdot e \) into the magnetic field formula, we get: \[ B = \frac{\mu_0 (n \cdot e)}{2r} \] ### Step 6: Final expression for the magnetic field Thus, the magnitude of the magnetic field produced at the center of the circular orbit is: \[ B = \frac{\mu_0 n e}{2r} \] ### Summary The magnetic field produced at the center of the circular orbit of an electron moving with \( n \) rotations per second and radius \( r \) is given by: \[ B = \frac{\mu_0 n e}{2r} \] ---

To find the magnetic field produced at the center of a circular orbit by an electron moving in that orbit, we can follow these steps: ### Step 1: Understand the problem We know that an electron is moving in a circular orbit of radius \( r \) and makes \( n \) rotations per second. We need to calculate the magnetic field at the center of this orbit. ### Step 2: Determine the current The current \( I \) produced by the moving charge can be calculated using the formula: \[ ...
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Knowledge Check

  • An electron moving in a circular orbit of radius r makes n rotations per second. The magnetic field produced at the centre has magnitude a

    A
    `(mu_0n^2e)/r`
    B
    `(mu_0n e)/(2r)`
    C
    `(mu_0n e)/(2pir)`
    D
    zero
  • A particle having charge 100 times that of an electron is revolving in a circular path of radius 0.8m with one rotation per second. The magnetic field produced at the centre is

    A
    `10^(-7) // mu_0`
    B
    `10^(-17) mu_0`
    C
    `10^(-6) mu_0 `
    D
    `10^(-15 ) // mu_0 `
  • An electron moving in a circular orbit of radius r makes n rotations per second per second. The magnetic moment of the orbital electron is

    A
    zero
    B
    `pi r^(2)n e`
    C
    `pi r^(2) n^(2)e`
    D
    `(r^(2) n e)/(2pi)`
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