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In an electromagnetic wave, the amplitud...

In an electromagnetic wave, the amplitude of electric field is `1 V/m`. The frequency of wave is `5xx10^(14)Hz`. The wave is propagating along `z`-axis. The average energy density of electric field, in `"joule"//m^(3)`,will be

A

`1.1xx10^(-11)`

B

`2.2xx10^(-12)`

C

`3.3xx10^(13)`

D

`4.4xx10^(-44)`

Text Solution

Verified by Experts

The correct Answer is:
B
Average energy density of electric field is given by
`u_(e)=(1)/(2)epsilon_(0)E^(2)=(1)/(2)epsilon_(0)((E_(0))/(sqrt(2)))^(2) =(1)/(4)epsilon_(0)E_(0)^(2)`
`=(1)/(4)xx8.85xx10^(-12)(I)^(2)=2.2xx10^(-12)J//m^(3)`
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Knowledge Check

  • In an electromagnetic wave, the amplitude of electric field is 10 V/m. The frequency of wave is 5 x10^(14) Hz, the wave is propagating along z–axis, then total average energy density of E.M. wave is

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    D
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