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Wavelength of light used in an optical i...

Wavelength of light used in an optical instrument are `lambda_(1)=400 Å ` and `lambda_(2)=5000 Å`, then ratio of their respective resolving power (corresponding to `lambda_(1)` and `lambda_(2))` is

A

`16:25`

B

`9:1`

C

`4:5`

D

`5:4`

Text Solution

Verified by Experts

The correct Answer is:
D
`R.P.=(1)/(lambda)implies((R.P.)_(1))/((R.P.)_(2))=(l_(2))/(l_(1))=(5)/(4)`
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Knowledge Check

  • Wavelength of light used in an optical instrument are lambda_(1) = 4000 Å and lambda_(2) = 5000Å then ratio of their respective resolving resolving powers (corresponding to lambda_(1) and lambda_(2) ) is

    A
    `16:25`
    B
    `9:1`
    C
    `4:5`
    D
    `5:4`

  • Wavelength of ligh used in an optical instrument are lamda_ =4000A and lamda_2=5000A , then ratio of their respective resolving powers (corresponding to lamda_1 and lamda_2 )

    A
    `16:25`
    B
    `9:1`
    C
    `4:5`
    D
    `5:4`

  • Wavelength of light used in an optical instrument are lamda_(1)=4500 Å and lamda_(2)=6000 Å. What is the ratio of the resolving powers corresponding to lamda_(1) and lamda_(2) ?

    A
    `3/4`
    B
    `4/3`
    C
    `9/(16)`
    D
    `(16)/(9)`

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