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Find the bond order of CO...

Find the bond order of ` CO`

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`CO= sigma1s^2, sigma^**1s^2, sigma2s^2, sigma2p_x^2 [(pi2p_y^2),(pi2p_z^2)],sigma^**2s^2`
`:.` Bond order of ` CO = 1/2 [ 10 - 4 ] = 3` .
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Knowledge Check

  • The bond order of CO is-

    A
    1
    B
    2
    C
    3
    D
    None of these

  • Bond order is

    A
    directily related to bond length
    B
    inversely related to bond length
    C
    inversely related to bond strength
    D
    never fractional

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