Find the bond order of ` CO`

Explanation

`CO= sigma1s^2, sigma^**1s^2, sigma2s^2, sigma2p_x^2 [(pi2p_y^2),(pi2p_z^2)],sigma^**2s^2`
`:.` Bond order of ` CO = 1/2 [ 10 - 4 ] = 3` .