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PCl5 in solid state exists as PCl4^+ and...

`PCl_5` in solid state exists as `PCl_4^+` and `PCl_6^-`. Also in some solvents it undergoes dissoctation as ` 2PCl_5 hArr PCl_2^+ +PCl_6^-`.
The geometry and hybridisation of `PCl_5` is :

A

trigonal bipyramid , `sp^3 d `

B

tetrahedral , `sp^3`

C

octahderal , `sp^3 d^2`

D

octahedral , `sp^3 d^2`

Text Solution

Verified by Experts

The correct Answer is:
A

It is a fact .
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Shape and hybridisation of PCl_(6)^(-) is

PCl_5 in solid state exists as PCl_4^+ and PCl_6^- Also in some solvents it undergoes dissoctation as 2PCl_5 hArr PCl_2^+ +PCl_6^- . The van't Hoff factor for diassociation of PCl_5 is (if alpha is its degree of disssociation) :

Knowledge Check

  • PCl_5 in solid state exists as PCl_4^+ and PCl_6^- Also in some solvents it undergoes dissoctation as 2PCl_5 hArr PCl_2^+ +PCl_6^- . The geometry and hybridisation of PCl_6^- is :

    A
    octahedral , `sp^3 d^2`
    B
    tetrahedral , `sp^3`
    C
    trigobal pyramid , `sp^3 d`
    D
    see - saw , `sp^3 `
  • PCl_5 in solid state exists as PCl_4^+ and PCl_6^- Also in some solvents it undergoes dissoctation as 2PCl_5 hArr PCl_2^+ +PCl_6^- . The geometry and hybridisation of PCl_4^+ is :

    A
    tetrahedral , `sp^3`
    B
    octahedral , `sp^3 d^2`
    C
    trigobal pyramid , `sp^3 d`
    D
    see - saw , `sp^3 d`
  • PCl_5 in solid state exists as PCl_4^+ and PCl_6^- Also in some solvents it undergoes dissoctation as 2PCl_5 hArr PCl_2^+ +PCl_6^- . Which statement is wrong ?

    A
    In `PCl_5`, all the `P -Cl` bonds are of same energy
    B
    `PCl_5` has no lone pair of electron
    C
    `PCl_5` is a white solid which melts at `167^(@)C`
    D
    ` PCl_5` gives white fumess with moist air
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    PCl_5 in solid state exists as PCl_4^+ and PCl_6^- Also in some solvents it undergoes dissoctation as 2PCl_5 hArr PCl_2^+ +PCl_6^- . The oxidation number of P in PCl_5 .PCl_4^+ and PCl_6^- are respectively :

    Hybridisation of PCl_(5) solid is :

    Solid PCl_5 exists as

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