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The following electrochemical cell has b...

The following electrochemical cell has been set up.
`Pt_((I))|Fe^(3+), Fe^(2+)(a=1)||Ce^(4+), CE^(3+)(a=1)|Pt_((II))`
If an ammmeteris connected between the two platinum electrode, prediect the direaction of flow of current. Will the current increases or decrease with time?

Text Solution

Verified by Experts

The `e.m.f.` of given cell `= E_(OP_(Fe^(2+)//Fe^(3+)))+E_(RP_(Ce^(3+)//Ce^(4+)))`
or `E_(cell)=E_(OP_(Fe^(2+)//Fe^(3+)))^(@)-(0.059)/(1)"log"([Fe^(3+)])/([Fe^(2+)])`
`+E_(RP_(Ce^(3+)//Ce^(4+)))^(@)+(0.059)/(1)"log"([Cr^(4+)])/([Ce^(3+)])`
`= E_(OP_(Fe^(2+)))^(@)+E_(RP_(Ce^(4+)))^(@)+(0.059)/(1)"log"([Ce^(4+)][Fe^(2+)])/([Ce^(3+)][Fe^(3+)])`
`= -0.77+1.61+(0.059)/(1)"log1 :. E_(cell) = 0.84V`
Thus, `Pt_((I))Fe^(3+)//Ce^(3+)` acts as anode and `Pt_((II))Ce^(4+)//Ce^(3+)` acts as cathode. The electrons flow from left to right and thus current will flow from right to left. The current strength will decrease with time.
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Knowledge Check

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