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50 mL of 0.1 M CuSO(4) solution is elect...

`50 mL` of `0.1 M CuSO_(4)` solution is electrolysed using `Pt` electrodes with a current of `0.965` ampere for a period of `1` minute. Assuming that volume of solution does not change during electrolysis, calculate `[Cu^(2+)], [H^(+)]` and `[SO_(4)^(2-)]` after electrolusis. What will be the concentration of each species if current is passed using `Cu` electrodes ?

Text Solution

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The correct Answer is:
`[Cu^(2+)] = 0.094M, [H^(+)] = 0.012 M, [SO_(4)^(2-)] = 0.1 M ;`
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Knowledge Check

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