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The distance between earth and moon is 3...

The distance between earth and moon is `3.8 xx 10^(8)m`. Determine the gravitational potential energy of earth-moon system. Given, mass of the earth `= 6 xx 10^(24) kg`, mass of moon `= 7.4 xx 10^(22)kg` and `G = 6.67 xx 10^(-11) Nm^(2) kg^(-2)`

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To determine the gravitational potential energy (U) of the Earth-Moon system, we can use the formula for gravitational potential energy between two point masses: \[ U = -\frac{G \cdot m_1 \cdot m_2}{r} \] Where: - \( G \) is the gravitational constant, \( 6.67 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2 \) ...
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The distance between the moon and earth is 3.8 xx 10^(8)m . Find the gravitional potential at the mid point of the joining them. Given that the mass of the earth is 6 xx 10^(24) kg , mass of moon = 7.4 xx 10^(22) kg and G = 6.67 xx 10^(11) Nm^(2)kg^(-2) .

Find th gravitational potenial energy of a body of mass 10 kg it is on the earths surface. [ M (earth ) = 6 xx 10^(24) kg, R (earth) = 6.4 xx 10^(6) m. G = 6.67 xx 10^(-11) N.m^(2)//kg^(2) ]

Knowledge Check

  • Determine the gravitational potential on the surface of earth, given that radius of the earth is 6.4 xx 10^(6) m : its mean density is 5.5 xx 10^(3)kg m^(-3) , G = 6.67 xx 10^(-11) Nm^(2) kg^(-2) .

    A
    `-6.297 xx 10^(7) J kg^(-1)`
    B
    `3.11 xx 10^(11) J kg^(-1)`
    C
    `4 xx 10^(8) J kg^(-1)`
    D
    `-2 xx 10^(9) J kg^(-1)`
  • Calculate the force of gravitation due to earth on a ball of 1 kg mass lying on the ground.(Mass of earth =6xx10^(24) kg Radius of earth =6.4xx10^(3) km and G=6.7xx10^(-11)Nm^(2)/Kg^(2)

    A
    `4.9 N`
    B
    `9.8 N`
    C
    `19.2 N`
    D
    None of the above
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    The distance between the earth and the moon is 3.85xx10^(8) metre. At what point in between the two will the gravitational field intensity be zero ? Mass of the earth is =6.0xx10^(24) kg, mass of the moon =7.26xx10^(22) kg

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    Find the gravitational potential energy of a body of mass 10 kg when it is on the earth's surface. [M(earth) =6xx10^(24)kg,"R (earth)"=6.4xx10^(6)m, G=6.67xx10^(-11)N.m^(2)//kg^(2)]

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