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The distance between earth and moon is 3...

The distance between earth and moon is `3.8 xx 10^(8)m`. Determine the gravitational potential energy of earth-moon system. Given, mass of the earth `= 6 xx 10^(24) kg`, mass of moon `= 7.4 xx 10^(22)kg` and `G = 6.67 xx 10^(-11) Nm^(2) kg^(-2)`

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To determine the gravitational potential energy (U) of the Earth-Moon system, we can use the formula for gravitational potential energy between two point masses: \[ U = -\frac{G \cdot m_1 \cdot m_2}{r} \] Where: - \( G \) is the gravitational constant, \( 6.67 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2 \) ...
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The distance between the moon and earth is 3.8 xx 10^(8)m . Find the gravitional potential at the mid point of the joining them. Given that the mass of the earth is 6 xx 10^(24) kg , mass of moon = 7.4 xx 10^(22) kg and G = 6.67 xx 10^(11) Nm^(2)kg^(-2) .

Determine the gravitational potential on the surface of earth, given that radius of the earth is 6.4 xx 10^(6) m : its mean density is 5.5 xx 10^(3)kg m^(-3) , G = 6.67 xx 10^(-11) Nm^(2) kg^(-2) .

The distance between the earth and the moon is 3.85xx10^(8) metre. At what point in between the two will the gravitational field intensity be zero ? Mass of the earth is =6.0xx10^(24) kg, mass of the moon =7.26xx10^(22) kg

The distance between earth and moon is about 3.8xx10^(5) km . At what point or points will the gravitational field strength of earth-moon system be zero? Given mass of earth is 81 times the moon's mass.

Find the gravitational potential energy of a body of mass 10 kg when it is on the earth's surface. [M(earth) =6xx10^(24)kg,"R (earth)"=6.4xx10^(6)m, G=6.67xx10^(-11)N.m^(2)//kg^(2)]

Find the escape velocity of a body from the earth. [M (earth ) = 6 xx 10^(24) kg, R ( earth) = 6.4 xx 10^(6) m. G = 6.67 xx 10^(-11) N.m^(2)//kg^(2)]

Determine the escape velocity of a body from the moon. Take the moon to be a uniform sphere of radius 1.76 xx 10^(6) m , and mass 7.36 xx 10^(22) kg . Given G=6.67 xx 10^(-11) Nm^(2) kg^(-2)

Calculate the force of gravitation due to earth on a ball of 1 kg mass lying on the ground.(Mass of earth =6xx10^(24) kg Radius of earth =6.4xx10^(3) km and G=6.7xx10^(-11)Nm^(2)/Kg^(2)

A satellite orbits the earth at a height of 400km above the surface. How much energy must be expanded to rocket the satellite out of the gravitational influence of earth? Mass of the satellite is 200kg, mass of earth =6.0 xx 10^(24) kg, radius of earth =6.4 xx 10^6 m , G=6.67xx10^(-11)Nm^2 kg^(-2).

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