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A sphere of mass 40 kg is attracted by a...

A sphere of mass `40 kg` is attracted by a second sphere of mass `60 kg` with a force equal to `4 mg`. If `G = 6 xx 10^(-11) N m^(2) kg^(-2)`, calculate the distance between them. Acceleration due to gravity `= 10 ms^(-2).`

Text Solution

Verified by Experts

Here, `M_(1) = 40 kg , M_(2) = 50 kg`,
`F = 0.02 g wt = 0.02 xx 10^(-3) kg wt`
`= 0.02 x 10^(-3) xx 9.8 N`
As `F = (GM_(1)M_(2))/(r^(2))` or `r = [(GM_(1)M_(2))/(F)]^(1//2)`
`:. R = [(6.67 xx 10^(-11) xx 40 xx 50)/(0.02 xx 10^(-3) xx 9.8)]^(1//2) = 0.026 m`
`= 2.6 cm`.
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Knowledge Check

  • Calculate the gravitational force of attraction between two spherical bodies, each of mass 1kg placed at 10m apart (G = 6.67 xx 10^(-11)Nm^(2)//kg^(2)) .

    A
    `6.67 xx 10^(-13)N`
    B
    `6.67xx 10^(-11)N`
    C
    `6.67 xx 10^(-7)N`
    D
    None of these

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