There is an air bubble of radius 2.0 mm in a liquid of surface tension `0.070 Nm^(-1)` and density `10^3 kg m^(-3)` The bubble is at a depth of 12.0 cm below the free surface of liquid. By what amount is the pressure inside the bubble is greater then the atmospheric pressure ? Use `g =10 m//s^2.`

Answer

`1270 Nm^(-2)`

Explanation

Pressure inside the bubble greater than atmospheric pressure ` =(2S)/(R ) + h rho g = (2xx0.070)/((2.0xx10^(-3)) + 0.12xx10^3 xx 10`
`=1270 Nm^(-2)`