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There is an air bubble of radius 2.0 mm ...

There is an air bubble of radius 2.0 mm in a liquid of surface tension `0.070 Nm^(-1)` and density `10^3 kg m^(-3)` The bubble is at a depth of 12.0 cm below the free surface of liquid. By what amount is the pressure inside the bubble is greater then the atmospheric pressure ? Use `g =10 m//s^2.`

Text Solution

Verified by Experts

The correct Answer is:
`1270 Nm^(-2)`
Pressure inside the bubble greater than atmospheric pressure ` =(2S)/(R ) + h rho g = (2xx0.070)/((2.0xx10^(-3)) + 0.12xx10^3 xx 10`
`=1270 Nm^(-2)`
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