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Eight rain drops of radius 1mm each fall...

Eight rain drops of radius `1mm` each falling downwards with a terminal velocity of `5 cm c^(-1)` coalesce to form a bigger drop. Find the terminal velocity of bigger drop.

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AI Generated Solution

To solve the problem of finding the terminal velocity of the bigger drop formed by the coalescence of eight smaller raindrops, we will follow these steps: ### Step 1: Calculate the Volume of the Smaller Drops The volume \( V \) of a single raindrop (which is spherical) can be calculated using the formula: \[ V = \frac{4}{3} \pi r^3 \] where \( r \) is the radius of the smaller drop. ...
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Knowledge Check

  • Eight drops of water, each of radius 2mm are falling through air at a terminal velcity of 8cms^-1 . If they coalesce to form a single drop, then the terminal velocity of combined drop will be

    A
    `32cms^-1`
    B
    `30cms^-1`
    C
    `28cms^-1`
    D
    `24cms^-1`

  • Eight equal drops of water each of radius r=2mm are falling through air with a terminal velocity of 16(cm)/(s) . The eight drops combine to form a big drop. Calculate the terminal velocity of big drop.

    A
    `16(cm)/(s)`
    B
    `32(cm)/(s)`
    C
    `64(cm)/(s)`
    D
    none of these

  • Eight equal droplets of water each ofradius rare falling through air with a terminal velocity of 7.5 cm//s^2 . The drops coalesce to form a big drop in air. What will be the terminal velocity of the big drop.

    A
    15 cm/s
    B
    20 cm/s
    C
    25 cm/s
    D
    30 cm/s

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    Two exactly simlar rain drops falling with terminal velocity of (2)^(1//3) ms^(-1) coalese to from a bigger drop Find the new terminal velocity of the bigger drop.

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