Water flows along the horizontal pipe of which the cross-section is not uniform. The pressure is `30 mm`. Of Hg where the velocity is `0.20 ms^(-1)`. Find the pressure at a point where the velocity is `1.20 ms^(-1)`.

Explanation

Here, `P_(1)=30mm` of Hg `=3.0 cm` of Hg
`=3.0xx13.6xx980 dyn e//cm^(2) , rho_(1)=13.6 g//c.c.`
`v_(1)=0.20 ms^(-1)=20 cm s^(-1)`,
`P_(1)=? , v_(2)=1.20 ms^(-1)=120 cm s^(-1)` ,
`P_(1)+(1)/(2) rho v_(1)^(2)=P_(2)+(1)/(2)rho v_(2)^(2)`
Piting the value find `P_(2)`, Which will the be `32984`
`dyn e//sq cm =(32984)/(13.6xx980)=2.48` cm of Hg