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Two solid spheres of same metal but of m...

Two solid spheres of same metal but of mass M and 8M fall simultaneously on a viscous liquid and their terminal velocitied are v and n v, then value of n is

A

16

B

8

C

4

D

2

Text Solution

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The correct Answer is:
To solve the problem, we need to analyze the relationship between the masses of the two spheres, their radii, and their terminal velocities as they fall through a viscous liquid. ### Step 1: Understand the relationship between mass and volume The mass \( m \) of a sphere can be expressed in terms of its volume \( V \) and density \( \rho \): \[ m = V \cdot \rho \] For a solid sphere, the volume \( V \) is given by: \[ V = \frac{4}{3} \pi r^3 \] Thus, we can express mass in terms of radius: \[ m = \frac{4}{3} \pi r^3 \cdot \rho \] ### Step 2: Relate the masses and radii of the spheres Let the mass of the first sphere be \( M \) and the mass of the second sphere be \( 8M \). Using the relationship derived above: 1. For the first sphere: \[ M = \frac{4}{3} \pi r_1^3 \cdot \rho \] 2. For the second sphere: \[ 8M = \frac{4}{3} \pi r_2^3 \cdot \rho \] ### Step 3: Find the relationship between the radii From the equations for mass, we can express the radii in terms of mass: \[ r_1^3 = \frac{3M}{4\pi \rho} \] \[ r_2^3 = \frac{3 \cdot 8M}{4\pi \rho} = 6M \] Taking the cube root gives us: \[ r_1 = \left(\frac{3M}{4\pi \rho}\right)^{1/3} \] \[ r_2 = \left(\frac{24M}{4\pi \rho}\right)^{1/3} = 2 \left(\frac{3M}{4\pi \rho}\right)^{1/3} = 2r_1 \] ### Step 4: Relate terminal velocities to radius The terminal velocity \( v_t \) of a sphere falling through a viscous liquid is given by: \[ v_t \propto r^2 \] Thus, we can write: \[ v_{t1} \propto r_1^2 \] \[ v_{t2} \propto r_2^2 \] ### Step 5: Calculate the ratio of terminal velocities Using the relationship \( r_2 = 2r_1 \): \[ v_{t2} \propto (2r_1)^2 = 4r_1^2 \] Now, we can write the ratio of terminal velocities: \[ \frac{v_{t1}}{v_{t2}} = \frac{r_1^2}{4r_1^2} = \frac{1}{4} \] This implies: \[ \frac{v}{nv} = \frac{1}{4} \] From this, we can conclude: \[ n = 4 \] ### Final Answer The value of \( n \) is \( 4 \). ---

To solve the problem, we need to analyze the relationship between the masses of the two spheres, their radii, and their terminal velocities as they fall through a viscous liquid. ### Step 1: Understand the relationship between mass and volume The mass \( m \) of a sphere can be expressed in terms of its volume \( V \) and density \( \rho \): \[ m = V \cdot \rho \] For a solid sphere, the volume \( V \) is given by: ...
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Knowledge Check

  • Two solid spheres of same metal but of mass M and 8M fall simultaneously on a viscous liquid and their terminal velocities are v and nv, then value of n is

    A
    16
    B
    8
    C
    4
    D
    2
  • Two solid spheres of came metal bar of mass 8M and 27M fall simultaneouslyon a viscous liquid and their terminal velocities are v and nv, then values n is

    A
    16
    B
    8.5
    C
    4
    D
    2.25
  • Two bodies of masses M and 27 M are allowed to fall on a viscous liquid simultaneously. The respective terminal velocities of bodies are V and kV. The value of k is

    A
    5
    B
    7
    C
    8
    D
    9
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