The binding energy of a H-atom considering an electron moving around a fixed nuclei (proton), is `B = - (me^(4))/(8n^(2)epsi_(0)^(2)h^(2))` (m= electron mass) If one decides to work in a frame of refrence where the electron is at rest, the proton would be movig around it. By similar arguments, the binding energy would be : `B = - (me^(4))/(8n^(2)epsi_(0)^(2)h^(2))` (M = proton mass) This last expression is not correct, because
A
n would not be integral
B
Bohr-quantisation applies only to electron
C
the frame in which the electrons is at rest is not inertial
D
the motion of the proton would not be in circular orbits, even approximately.
Text Solution
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The correct Answer is:
C
In a hydrogen atom, electron revolving around a fixed proton nucleus has some centripetal acceleration. Therefore, its frame of reference in no inertial. In the fram of reference, where the electron is at rest, the given expression cannot be true for binding energy as the frame in which electrons is at rest would not be inertial. Choice (c) is correct.
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PRADEEP-ATOMS AND NUCLEI-NCERT Multiple choice (I) questions 2
