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e^(x-y)(sinx+cosx)dx+(cosy-siny)dy=0...

`e^(x-y)(sinx+cosx)dx+(cosy-siny)dy=0`

A

`e^(x-y)(sinx+cosy)=c`

B

`e^(x)sinx=ce^(y)cosy`

C

`e^(x)sinx+e^(y)cosy=c`

D

`e^(y)siny-e^(x)cosx=c`

Text Solution

Verified by Experts

The correct Answer is:
C
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