The angular velocity of rotation of a planet of mass M and radius R, at which the matter start to escape from its equator is

Options

A. `sqrt((2GM)/(R^(3)))`
B. `sqrt((2GM)/(R ))`
C. `sqrt((2G^(2)M)/(R ))`
D. `sqrt((2GM^(2))/(R ))`

Answer

A

Explanation

`V_(E )=sqrt((2GM)/(R ))`
`therefore omega=(V_(E ))/(R )=(1)/(R )sqrt((2GM)/(R ))=sqrt((2GM)/(R^(3)))`