Two waves having the intensities in the ratio of `9 : 1` produce interference. The ratio of maximum to minimum intensity is equal to

Options

A. `10:8`
B. `2:1`
C. `9:1`
D. `4:1`

Answer

D

Explanation

`Iprop(amp)^(2)" "therefore ` amplitudes are in the ratio 3:1.
`therefore`maximum amplitude=`3+1=4and`
minimum amplitude`=3-1=2`
`therefore (I_(max))/(I_("min"))=(4^(2))/(2^(2))=4:1`