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Bisector of angleB" and "angle C " in "D...

Bisector of `angleB" and "angle C " in "DeltaABC` meet each other at P. Line Ap cuts the side BC at Q. Then prove that : `(AP)/(PQ)=(AB+BC)/(BC)`

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The correct Answer is:
`therefore(AP)/(PQ)=(AB+AC)/(BC)`
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